(1/3)^2x+3=9X-5

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Solution for (1/3)^2x+3=9X-5 equation: 



(1/3)^2x+3=9x-5

We move all terms to the left:

(1/3)^2x+3-(9x-5)=0



Domain of the equation: 3)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^2x-(9x-5)+3=0

We get rid of parentheses

(+1/3)^2x-9x+5+3=0

We multiply all the terms by the denominator


(+1-9x*3)^2x+5*3)^2x+3*3)^2x=0

We add all the numbers together, and all the variables

(-9x*3+1)^2x+5*3)^2x+3*3)^2x=0

Wy multiply elements

45x^2+(-9x*3+1)^2x=0

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